If the momentum of an electron is $1.95 \times 10 ^ { - 27 } \mathrm {~kg} \cdot \mathrm { m } / \mathrm { s }$, what is its de Broglie wavelength? $( h =$ $6.626 \times 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s }$ )
A) $420 \mathrm {~nm}$
B) $170 \mathrm {~nm}$
C) $340 \mathrm {~nm}$
D) $210 \mathrm {~nm}$
E) $520 \mathrm {~nm}$

Question

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The Answer of If the momentum of an electron is $1.95 \times 10 ^ { - 27 } \mathrm {~kg} \cdot \mathrm { m } / \mathrm { s }$, what is its de Broglie wavelength? $( h =$ $6.626 \times 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s }$ )
A) $420 \mathrm {~nm}$
B) $170 \mathrm {~nm}$
C) $340 \mathrm {~nm}$
D) $210 \mathrm {~nm}$
E) $520 \mathrm {~nm}$

If the Momentum of an Electron Is 1.95×10−27 kg⋅m/s1.95 \times 10 ^ { - 27 } \mathrm {~kg} \cdot \mathrm { m } / \mathrm { s }1.95×10−27 kg⋅m/s

If the Momentum of an Electron Is $1.95 \times 10 ^ { - 27 } \mathrm {~kg} \cdot \mathrm { m } / \mathrm { s }$