A metal has a work function of $4.50 \mathrm { eV }$. Find the maximum kinetic energy of the photoelectrons if light of wavelength $250 \mathrm {~nm}$ shines on the metal. $\left( 1 \mathrm { eV } = 1.60 \times 10 ^ { - 19 } \mathrm {~J} , c = 3.00 \times 10 ^ { 8 } \mathrm {~m} / \mathrm { s } , h = 6.626 \right.$ × $10 ^{- 34} \mathrm {~J} \cdot \mathrm { s }$ ) A) $0.47 \mathrm { eV }$ B) $0.37 \mathrm { eV }$ C) $0.53 \mathrm { eV }$ D) $0.00 \mathrm { eV }$

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Quizplus · Accepted Answer

The energy of the incident photons is calculated using $E = \frac{hc}{\lambda}$. Substituting the given values, $E = \frac{6.626 \times 10^{-34} \times 3.00 \times 10^8}{250 \times 10^{-9}}$ J, which converts to approximately $4.97 \mathrm{eV}$. The maximum kinetic energy of the photoelectrons is given by $K.E. = E - \text{work function} = 4.97 \mathrm{eV} - 4.50 \mathrm{eV} = 0.47 \mathrm{eV}$.

A Metal Has a Work Function Of 4.50eV4.50 \mathrm { eV }4.50eV

A Metal Has a Work Function Of $4.50 \mathrm { eV }$