An ideal spring with a force constant (spring constant) of 15 N/m is initially compressed by 3.0 cm from its uncompressed position. How much work is required to compress the spring an additional
4)0 cm?
A) 0.030 J
B) 0.024 J
C) 0.012 J
D) 0.0068 J

Question

Quizplus · Accepted Answer

The work done in compressing a spring is given by the formula W = (1/2)kx^2, where k is the spring constant and x is the displacement from the equilibrium position. In this case, the spring constant is 15 N/m and the initial displacement is 3.0 cm = 0.03 m. The additional displacement is 4.0 cm = 0.04 m. So, the work required to compress the spring an additional 4.0 cm is:W = (1/2)kx^2 = (1/2)(15 N/m)(0.04 m)^2 = 0.030 J

An Ideal Spring with a Force Constant (Spring Constant) of 15