If 4.0 J of work are performed in stretching an ideal spring with a spring constant (force constant) of 2500 N/m, by what distance is the spring stretched?
A) 5.7 cm
B) 3.2 cm
C) 3.2 m
D) 0.3 cm
E) 5.7 m

Question

Quizplus · Accepted Answer

The work done in stretching a spring is given by the equation W = 1/2 kx^2, where W is the work done, k is the spring constant, and x is the distance the spring is stretched. In this case, W = 4.0 J, k = 2500 N/m, and we need to find x. Solving for x, we get x = sqrt(2W/k) = sqrt(2(4.0 J)/(2500 N/m)) = 0.057 m = 5.7 cm.

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