A 100-N force has a horizontal component of 80 N and a vertical component of 60 N. The force is applied to a cart on a level frictionless floor. The cart starts from rest and moves 2.0 m horizontally
Along the floor due to this force. What is the cart's final kinetic energy?
A) 120 J
B) 160 J
C) zero
D) 200 J

Question

Quizplus · Accepted Answer

The work done on the cart is equal to the force times the distance moved in the direction of the force. Since the force has a horizontal component of 80 N and the cart moves 2.0 m horizontally, the work done (and thus the kinetic energy gained) is $W = F \times d = 80 \, \text{N} \times 2.0 \, \text{m} = 160 \, \text{J}$.

A 100-N Force Has a Horizontal Component of 80 N