Skewness can be measured by Pearson's index of skewness:
$$I = \frac { 3 ( \bar { x } - \text { median } ) } { s }$$
If $\mathrm { I } \geq 1.00$ or $\mathrm { I } \leq - 1.00$, the data can be considered significantly skewed. Would you expect that incomes of all adults in the US would be skewed? In which direction? Why? Would you expect that for these incomes, Pearson's index of skewness would be greater than 1, smaller than $- 1$, or between $- 1$ and 1 ?

Question

Skewness can be measured by Pearson's index of skewness: 
$$I = \frac { 3 ( \bar { x } - \text { median } ) } { s }$$
If $\mathrm { I } \geq 1.00$ or $\mathrm { I } \leq - 1.00$, the data can be considered significantly skewed. Would you expect that incomes of all adults in the US would be skewed? In which direction? Why? Would you expect that for these incomes, Pearson's index of skewness would be greater than 1, smaller than $- 1$, or between $- 1$ and 1 ?

Quizplus · Accepted Answer

The Answer of Skewness can be measured by Pearson's index of skewness: 
$$I = \frac { 3 ( \bar { x } - \text { median } ) } { s }$$
If $\mathrm { I } \geq 1.00$ or $\mathrm { I } \leq - 1.00$, the data can be considered significantly skewed. Would you expect that incomes of all adults in the US would be skewed? In which direction? Why? Would you expect that for these incomes, Pearson's index of skewness would be greater than 1, smaller than $- 1$, or between $- 1$ and 1 ?

Skewness Can Be Measured by Pearson's Index of Skewness I=3(xˉ− median )sI = \frac { 3 ( \bar { x } - \text { median } ) } { s }I=s3(xˉ− median )​

Skewness Can Be Measured by Pearson's Index of Skewness $I = \frac { 3 ( \bar { x } - \text { median } ) } { s }$