Find the mean of the given probability distribution.
-In a certain town, 40% of adults have a college degree. The accompanying table describes the probability distribution for the number of adults (among 4 randomly selected adults) who have a college degree.

$\begin{array}{c|r}
\mathrm{x} & \mathrm{P}(\mathrm{x}) \
\hline 0 & 0.1296 \
1 & 0.3456 \
2 & 0.3456 \
3 & 0.1536 \
4 & 0.0256
\end{array}$

A) $\mu = 2.00$
B) $\mu = 1.50$
C) $\mu = 1.60$
D) $\mu = 1.73$

Question

Find the mean of the given probability distribution.
-In a certain town, 40% of adults have a college degree. The accompanying table describes the probability distribution for the number of adults (among 4 randomly selected adults) who have a college degree.

$\begin{array}{c|r}
\mathrm{x} & \mathrm{P}(\mathrm{x}) \
\hline 0 & 0.1296 \
1 & 0.3456 \
2 & 0.3456 \
3 & 0.1536 \
4 & 0.0256
\end{array}$

A) $\mu = 2.00$
B) $\mu = 1.50$
C) $\mu = 1.60$
D) $\mu = 1.73$

Quizplus · Accepted Answer

The mean of a probability distribution is calculated as $\mu = \sum [x \cdot P(x)]$. For this distribution: $\mu = (0 \cdot 0.1296) + (1 \cdot 0.3456) + (2 \cdot 0.3456) + (3 \cdot 0.1536) + (4 \cdot 0.0256) = 1.60$.

Find the Mean of the Given Probability Distribution xP(x)00.129610.345620.345630.153640.0256\begin{array}{c|r}\mathrm{x} & \mathrm{P}(\mathrm{x}) \\\hline 0 & 0.1296 \\1 & 0.3456 \\2 & 0.3456 \\3 & 0.1536 \\4 & 0.0256\end{array}x01234​P(x)0.12960.34560.34560.15360.0256​​

Find the Mean of the Given Probability Distribution $\begin{array}{c|r}\mathrm{x} & \mathrm{P}(\mathrm{x}) \\\hline 0 & 0.1296 \\1 & 0.3456 \\2 & 0.3456 \\3 & 0.1536 \\4 & 0.0256\end{array}$