The number of visits to a certain web site were counted each day of a particular week. Thi are given in the following table.
$\begin{array}{cc}
\hline \text { Day } & \text { Number of Visits } \
\hline \text { Sunday } & 144 \
\text { Monday } & 103 \
\text { Tuesday } & 136 \
\text { Wednesday } & 124 \
\text { Thursday } & 127 \
\text { Friday } & 145 \
\text { Saturday } & 156 \
\hline
\end{array}$

Test the hypothesis that web site visits are equally likely to occur on any day of the week. $\alpha = 0.05$ level of significance.
A) Reject $H _ { 0 }$. The visits do not appear to be equally likely.
B) Do not reject $H _ { 0 }$. The visits may be equally likely.

Question

The number of visits to a certain web site were counted each day of a particular week. Thi are given in the following table.
$\begin{array}{cc}
\hline \text { Day } & \text { Number of Visits } \
\hline \text { Sunday } & 144 \
\text { Monday } & 103 \
\text { Tuesday } & 136 \
\text { Wednesday } & 124 \
\text { Thursday } & 127 \
\text { Friday } & 145 \
\text { Saturday } & 156 \
\hline
\end{array}$

Test the hypothesis that web site visits are equally likely to occur on any day of the week. $\alpha = 0.05$ level of significance.
A) Reject $H _ { 0 }$. The visits do not appear to be equally likely.
B) Do not reject $H _ { 0 }$. The visits may be equally likely.

Quizplus · Accepted Answer

To test the hypothesis that visits are equally likely on any day, we calculate the expected frequency for each day under the null hypothesis and compare it with the observed frequencies using a chi-square test. The total number of visits is $144 + 103 + 136 + 124 + 127 + 145 + 156 = 935$. Under the null hypothesis, we expect each day to have $935 / 7 \approx 133.57$ visits. The observed frequencies significantly deviate from the expected frequencies, leading to the rejection of the null hypothesis at the $\alpha = 0.05$ level, indicating that visits are not equally likely on any day of the week.

The Number of Visits to a Certain Web Site Were