$$\begin{array}{l}
\text { For the data set below, find the upper outlier boundary. }\
\begin{array} { l l l l l l l l l l l }
\hline 154 & 160 & 146 & 146 & 131 & 148 & 164 & 199 & 169 & 139 & 165 \
\hline
\end{array}
\end{array}$$
A) 19
B) 193.5
C) 165
D) 199

Question

$$\begin{array}{l}
\text { For the data set below, find the upper outlier boundary. }\
\begin{array} { l l l l l l l l l l l } 
\hline 154 & 160 & 146 & 146 & 131 & 148 & 164 & 199 & 169 & 139 & 165 \
\hline
\end{array}
\end{array}$$
A) 19
B) 193.5
C) 165
D) 199

Quizplus · Accepted Answer

To find the upper outlier boundary, first, we need to calculate the first quartile (Q1), the third quartile (Q3), and then use these to find the interquartile range (IQR). The upper outlier boundary is then Q3 + 1.5*IQR.1. Arrange the data in ascending order: 131, 139, 146, 146, 148, 154, 160, 164, 165, 169, 199.2. Find Q1 (the median of the first half of the data, not including the median of the dataset if the number of data points is odd): Median of 131, 139, 146, 146, 148 = 146.3. Find Q3 (the median of the second half of the data): Median of 160, 164, 165, 169, 199 = 165.4. Calculate IQR = Q3 - Q1 = 165 - 146 = 19.5. Calculate the upper outlier boundary = Q3 + 1.5*IQR = 165 + 1.5*19 = 165 + 28.5 = 193.5.

A) 19 B) 193

A) 19
B) 193