A group of 6 children are choosing colored pencils to draw a picture. Each child is allowed to select one color. The available colors are green, red, and blue. If the second
Child refuses to use red pencils and the third child refuses to use blue pencils, then how
Many ways are there for the children to choose pencils? Assume that there are 12 pencils
Available of each color, and different children are allowed to choose the same color.
A) 36
B) 243
C) 729
D) 324

Question

Quizplus · Accepted Answer

For the first child, there are 3 choices (green, red, blue). For the second child, there are only 2 choices (green, blue) because they refuse to use red. For the third child, there are also 2 choices (green, red) because they refuse to use blue. For the remaining 3 children, there are no restrictions, so each of them has 3 choices. Therefore, the total number of ways is 3 * 2 * 2 * 3 * 3 * 3 = 324.

A Group of 6 Children Are Choosing Colored Pencils to Draw