Fill in the missing value so that the following table represents a probability distribution.
$\begin{array}{c|cccl}
x & -4 & -3 & -2 & -1 \
\hline P(x) & 0.42 & 0.08 & ? & 0.05
\end{array}$
A) 0.26
B) 0.45
C) 0.33
D) 0.25

Question

Fill in the missing value so that the following table represents a probability distribution.
$\begin{array}{c|cccl}
x & -4 & -3 & -2 & -1 \
\hline P(x) & 0.42 & 0.08 & ? & 0.05
\end{array}$ 
A) 0.26
B) 0.45
C) 0.33
D) 0.25

Quizplus · Accepted Answer

The Answer of Fill in the missing value so that the following table represents a probability distribution.
$\begin{array}{c|cccl}
x & -4 & -3 & -2 & -1 \
\hline P(x) & 0.42 & 0.08 & ? & 0.05
\end{array}$ 
A) 0.26
B) 0.45
C) 0.33
D) 0.25

Fill in the Missing Value So That the Following Table x−4−3−2−1P(x)0.420.08?0.05\begin{array}{c|cccl}x & -4 & -3 & -2 & -1 \\\hline P(x) & 0.42 & 0.08 & ? & 0.05\end{array}xP(x)​−40.42​−30.08​−2?​−10.05​​

Fill in the Missing Value So That the Following Table $\begin{array}{c|cccl}x & -4 & -3 & -2 & -1 \\\hline P(x) & 0.42 & 0.08 & ? & 0.05\end{array}$