The following MINITAB output presents a $95 \%$ confidence interval.
$\begin{array}{ccccc}
\hline{\text { The assumed sigma }=7.9655} & \
\text { Variable } & \mathrm{N} & \text { Mean } & \text { SE Mean } & 95 \% \mathrm{CI} \
\mathrm{x} & 56 & 53.559 & 1.0644 & (51.473,55.645) \
\hline
\end{array}$

Find the sample size needed so that the $99 \%$ confidence interval will have a margin of err $1.1$. rror of
A) 284
B) 15
C) 348
D) 202

Question

The following MINITAB output presents a $95 \%$ confidence interval.
$\begin{array}{ccccc}
\hline{\text { The assumed sigma }=7.9655} & \
\text { Variable } & \mathrm{N} & \text { Mean } & \text { SE Mean } & 95 \% \mathrm{CI} \
\mathrm{x} & 56 & 53.559 & 1.0644 & (51.473,55.645) \
\hline
\end{array}$

Find the sample size needed so that the $99 \%$ confidence interval will have a margin of err $1.1$. rror of
A) 284
B) 15
C) 348
D) 202

Quizplus · Accepted Answer

The Answer of The following MINITAB output presents a $95 \%$ confidence interval.
$\begin{array}{ccccc}
\hline{\text { The assumed sigma }=7.9655} & \
\text { Variable } & \mathrm{N} & \text { Mean } & \text { SE Mean } & 95 \% \mathrm{CI} \
\mathrm{x} & 56 & 53.559 & 1.0644 & (51.473,55.645) \
\hline
\end{array}$

Find the sample size needed so that the $99 \%$ confidence interval will have a margin of err $1.1$. rror of
A) 284
B) 15
C) 348
D) 202

The Following MINITAB Output Presents A 95%95 \%95% Confidence Interval Find the Sample Size Needed So That The

The Following MINITAB Output Presents A $95 \%$ Confidence Interval Find the Sample Size Needed So That The