Solve the inequality. Write your answer in interval notation. $26 3 x$ and $- 1 + 2 x \geq - 8$
A) { }
B) $\left( - \infty , - \frac { 7 } { 2 } \right) \cup \left[ \left( \frac { 26 } { 3 } , \infty \right) \right.$
C) $\left[ - \frac { 7 } { 2 } , \frac { 26 } { 3 } \right]$
D) $\left[ - \frac { 26 } { 3 } , \frac { 7 } { 2 } \right]$

Question

Solve the inequality. Write your answer in interval notation. $26 > 3 x$ and $- 1 + 2 x \geq - 8$
A) {  }
B) $\left( - \infty , - \frac { 7 } { 2 } \right) \cup \left[ \left( \frac { 26 } { 3 } , \infty \right) \right.$
C) $\left[ - \frac { 7 } { 2 } , \frac { 26 } { 3 } \right]$
D) $\left[ - \frac { 26 } { 3 } , \frac { 7 } { 2 } \right]$

Quizplus · Accepted Answer

Solving the inequalities: $26 > 3x$ gives $x < \frac{26}{3}$, and $-1 + 2x \geq -8$ simplifies to $2x \geq -7$, which gives $x \geq -\frac{7}{2}$. Combining these gives the interval $\left[ -\frac{7}{2}, \frac{26}{3} \right]$.

Solve the Inequality 26>3x26 > 3 x26>3x And −1+2x≥−8- 1 + 2 x \geq - 8−1+2x≥−8

Solve the Inequality $26 > 3 x$ And $- 1 + 2 x \geq - 8$