Solve the inequality. Write the solution set in interval notation. $11 \leq 6 ( n + 4 ) - 4 n$
A) $\left( - \infty , - \frac { 13 } { 2 } \right)$
B) $\left( - \frac { 13 } { 2 } , \infty \right)$
C) $\left[ - \frac { 13 } { 2 } , \infty \right]$
D) $[ 4,11 ]$

Question

Quizplus · Accepted Answer

First, simplify the inequality: $11 \leq 6(n + 4) - 4n$ becomes $11 \leq 6n + 24 - 4n$, which simplifies to $11 \leq 2n + 24$. Subtracting 24 from both sides gives $-13 \leq 2n$, and dividing by 2 gives $-\frac{13}{2} \leq n$. This means $n$ is greater than or equal to $-\frac{13}{2}$, so the correct interval notation is $\left[ - \frac { 13 } { 2 } , \infty \right]$.

Solve the Inequality 11≤6(n+4)−4n11 \leq 6 ( n + 4 ) - 4 n11≤6(n+4)−4n

Solve the Inequality $11 \leq 6 ( n + 4 ) - 4 n$