The mass of an object is equal to its density times its volume, or m = DV.
a. Solve this equation for $D$.
b. The mass of a sample of iron ore is $9.92$ grams and its volume is $3.1 \mathrm {~cm} ^ { 3 }$. Find the density of the o Round to one decimal place.
A) a. $D = m - V$
b. $6.8 \mathrm {~g} / \mathrm { cm } ^ { 3 }$

B) а. $D = \frac { V } { m }$
b. $0.3 \mathrm {~g} / \mathrm { cm } ^ { 3 }$

C) a. $D = \frac { m } { V }$
b. $3.2 \mathrm {~g} / \mathrm { cm } ^ { 3 }$

D) a. $D = m V$
b. $30.8 \mathrm {~g} / \mathrm { cm } ^ { 3 }$

Question

The mass of an object is equal to its density times its volume, or m = DV. 
a. Solve this equation for $D$.
b. The mass of a sample of iron ore is $9.92$ grams and its volume is $3.1 \mathrm {~cm} ^ { 3 }$. Find the density of the o Round to one decimal place.
A) a. $D = m - V$
b. $6.8 \mathrm {~g} / \mathrm { cm } ^ { 3 }$

B) а. $D = \frac { V } { m }$
b. $0.3 \mathrm {~g} / \mathrm { cm } ^ { 3 }$

C) a. $D = \frac { m } { V }$
b. $3.2 \mathrm {~g} / \mathrm { cm } ^ { 3 }$

D) a. $D = m V$
b. $30.8 \mathrm {~g} / \mathrm { cm } ^ { 3 }$

Quizplus · Accepted Answer

a. To solve for $D$, divide both sides of the equation $m = DV$ by $V$, resulting in $D = \frac{m}{V}$. b. The density is found by dividing the mass by the volume, $9.92 \, \text{grams} \div 3.1 \, \text{cm}^3 = 3.2 \, \text{g/cm}^3$.

The Mass of an Object Is Equal to Its Density DDD

The Mass of an Object Is Equal to Its Density $D$