Find the nth term of the geometric sequence. $$\frac { 1 } { 2 } , 2,8,32 , \ldots$$
A) $\frac { 1 } { 4 } ( 2 ) ^ { n - 1 }$
B) $\frac { 1 } { 2 } ( 4 ) ^ { n - 1 }$
C) $\frac { 1 } { 4 } ( 2 ) ^ { n }$
D) $\frac { 1 } { 2 } ( 4 ) ^ { n }$

Question

Quizplus · Accepted Answer

The first term is $\frac{1}{2}$ and the common ratio is 4. The nth term of a geometric sequence is given by $a \cdot r^{n-1}$, where $a$ is the first term and $r$ is the common ratio. Thus, the nth term is $\frac{1}{2} \cdot 4^{n-1}$.

Find the Nth Term of the Geometric Sequence 12,2,8,32,…\frac { 1 } { 2 } , 2,8,32 , \ldots21​,2,8,32,…

Find the Nth Term of the Geometric Sequence $\frac { 1 } { 2 } , 2,8,32 , \ldots$