Find the nth term of the geometric sequence. -8, 16, -32, 64, ...
A) $- 8 ( - 2 ) ^ { n - 1 }$
B) $- 2 ( - 8 ) ^ { n }$
C) $- 2 ( - 8 ) ^ { n - 1 }$
D) $- 8 ( - 2 ) ^ { n }$

Question

Find the nth term of the geometric sequence. -8, 16, -32, 64, ... 
A) $- 8 ( - 2 ) ^ { n - 1 }$
B) $- 2 ( - 8 ) ^ { n }$
C) $- 2 ( - 8 ) ^ { n - 1 }$
D) $- 8 ( - 2 ) ^ { n }$

Quizplus · Accepted Answer

The sequence is a geometric sequence with the first term $a = -8$ and common ratio $r = -2$ (since each term is -2 times the previous term). The nth term of a geometric sequence is given by $a \cdot r^{n-1}$. Substituting $a = -8$ and $r = -2$, we get $-8(-2)^{n-1}$.

Find the Nth Term of the Geometric Sequence −8(−2)n−1- 8 ( - 2 ) ^ { n - 1 }−8(−2)n−1

Find the Nth Term of the Geometric Sequence $- 8 ( - 2 ) ^ { n - 1 }$