Solve the system of equations. $$\begin{aligned}
10 x + 20 z & = 22 \
y - 3 z & = - 2 \
x - 5 y & = 2
\end{aligned}$$
A) $\left( \frac { 11 } { 5 } , 3,0 \right)$
B) $\left( 1 , - \frac { 1 } { 5 } , \frac { 3 } { 5 } \right)$
C) $( 0,7 , - 9 )$
D) $\left( 1,3 , \frac { 3 } { 5 } \right)$

Question

Quizplus · Accepted Answer

To solve the system of equations, we can use substitution or elimination. The given system is:1) $10x + 20z = 22$2) $y - 3z = -2$3) $x - 5y = 2$From equation 3, we can express $x$ in terms of $y$: $x = 5y + 2$.Substituting $x$ in equation 1 gives us a relation between $y$ and $z$, and using equation 2, we can find the values of $y$ and $z$. Substituting these values back into the expression for $x$ gives us the solution for $x$.After solving, we find that the solution that matches is $\left( 1 , - \frac { 1 } { 5 } , \frac { 3 } { 5 } \right)$, which corresponds to choice B.

Solve the System of Equations 10x+20z=22y−3z=−2x−5y=2\begin{aligned}10 x + 20 z & = 22 \\y - 3 z & = - 2 \\x - 5 y & = 2\end{aligned}10x+20zy−3zx−5y​=22=−2=2​

Solve the System of Equations $\begin{aligned}10 x + 20 z & = 22 \\y - 3 z & = - 2 \\x - 5 y & = 2\end{aligned}$