Solve the system by the addition method. $$\begin{array} { l }
\frac { 1 } { 4 } x + y = - \frac { 7 } { 5 } \
x + 4 y = - 2.6
\end{array}$$
A) No solution; \{ \} ; inconsistent system
B) $( 0 , - 0.65 )$
C) Infinitely many solutions; $\left\{ ( x , y ) \mid y = - \frac { 1 } { 4 } x - \frac { 7 } { 5 } \right\}$; dependent system
D) $( 0 , - 1.4 )$

Question

Solve the system by the addition method. $$\begin{array} { l } 
\frac { 1 } { 4 } x + y = - \frac { 7 } { 5 } \
x + 4 y = - 2.6
\end{array}$$
A) No solution; \{ \} ; inconsistent system
B) $( 0 , - 0.65 )$
C) Infinitely many solutions; $\left\{ ( x , y ) \mid y = - \frac { 1 } { 4 } x - \frac { 7 } { 5 } \right\}$; dependent system
D) $( 0 , - 1.4 )$

Quizplus · Accepted Answer

The Answer of Solve the system by the addition method. $$\begin{array} { l } 
\frac { 1 } { 4 } x + y = - \frac { 7 } { 5 } \
x + 4 y = - 2.6
\end{array}$$
A) No solution; \{ \} ; inconsistent system
B) $( 0 , - 0.65 )$
C) Infinitely many solutions; $\left\{ ( x , y ) \mid y = - \frac { 1 } { 4 } x - \frac { 7 } { 5 } \right\}$; dependent system
D) $( 0 , - 1.4 )$

Solve the System by the Addition Method 14x+y=−75x+4y=−2.6\begin{array} { l } \frac { 1 } { 4 } x + y = - \frac { 7 } { 5 } \\x + 4 y = - 2.6\end{array}41​x+y=−57​x+4y=−2.6​

Solve the System by the Addition Method $\begin{array} { l } \frac { 1 } { 4 } x + y = - \frac { 7 } { 5 } \\x + 4 y = - 2.6\end{array}$