Factor the expression that defines the function. $k ( w ) = w ^ { 3 } + 7 w ^ { 2 } + 4 w + 28$
A) $k ( w ) = ( w + 7 ) \left( w ^ { 2 } + 4 \right)$
B) $k ( w ) = w ^ { 2 } ( w + 7 ) + 2 ( 2 w + 14 )$
C) $k ( w ) = ( w + 7 ) ( w + 2 ) ( w - 2 )$
D) $k ( w ) = w ^ { 3 } + 7 w ^ { 2 } + 4 w + 28$ (Expression is prime)

Question

Quizplus · Accepted Answer

The expression $w^3 + 7w^2 + 4w + 28$ can be factored by grouping: $w^2(w + 7) + 4(w + 7)$, which simplifies to $(w + 7)(w^2 + 4)$.

Factor the Expression That Defines the Function k(w)=w3+7w2+4w+28k ( w ) = w ^ { 3 } + 7 w ^ { 2 } + 4 w + 28k(w)=w3+7w2+4w+28

Factor the Expression That Defines the Function $k ( w ) = w ^ { 3 } + 7 w ^ { 2 } + 4 w + 28$