Multiply the radical expressions. $( \sqrt { 7 x - 3 } + 4 ) ^ { 2 }$
A) $7 x + 4 \sqrt { 7 x - 3 } + 13$
B) $7 x + 8 \sqrt { 7 x - 3 } + 13$
C) $7 x + 13$
D) $7 x + 1$

Question

Quizplus · Accepted Answer

To multiply the given expression $( \sqrt { 7 x - 3 } + 4 ) ^ { 2 }$, we apply the formula $(a+b)^2 = a^2 + 2ab + b^2$. Here, $a = \sqrt{7x-3}$ and $b = 4$. Squaring $a$ gives $7x-3$, multiplying $2ab$ gives $8\sqrt{7x-3}$, and squaring $b$ gives $16$. Adding these results gives $7x - 3 + 8\sqrt{7x-3} + 16$, which simplifies to $7x + 8\sqrt{7x-3} + 13$.

Multiply the Radical Expressions (7x−3+4)2( \sqrt { 7 x - 3 } + 4 ) ^ { 2 }(7x−3​+4)2

Multiply the Radical Expressions $( \sqrt { 7 x - 3 } + 4 ) ^ { 2 }$