Solve the rational inequality. Write the answer in interval notation. $$\frac { ( x + 7 ) ^ { 2 } } { x } 0$$
A) $( 0 , \infty )$
B) $( - 7 , \infty )$
C) $( 7 , \infty )$
D) $( - \infty , 0 ) \cup ( 0 , \infty )$

Question

Solve the rational inequality. Write the answer in interval notation. $$\frac { ( x + 7 ) ^ { 2 } } { x } > 0$$
A) $( 0 , \infty )$
B) $( - 7 , \infty )$
C) $( 7 , \infty )$
D) $( - \infty , 0 ) \cup ( 0 , \infty )$

Quizplus · Accepted Answer

The inequality is true when the numerator is positive and the denominator is positive, or when the numerator is negative and the denominator is negative. The numerator is positive when x > -7, and the denominator is positive when x > 0. Therefore, the inequality is true when x > 0.

Solve the Rational Inequality (x+7)2x>0\frac { ( x + 7 ) ^ { 2 } } { x } > 0x(x+7)2​>0

Solve the Rational Inequality $\frac { ( x + 7 ) ^ { 2 } } { x } > 0$