Find the vertex of $g ( x ) = \frac { 1 } { 3 } \left( x + \frac { 24 } { 5 } \right) ^ { 2 } - \frac { 5 } { 24 }$.
A) $\left( - \frac { 24 } { 5 } , - \frac { 5 } { 24 } \right)$
B) $\left( \frac { 5 } { 24 } , \frac { 24 } { 5 } \right)$
C) $\left( - \frac { 5 } { 24 } , - \frac { 24 } { 5 } \right)$
D) $\left( \frac { 24 } { 5 } , - \frac { 5 } { 24 } \right)$

Question

Quizplus · Accepted Answer

The vertex form of a quadratic function is $f(x) = a(x - h)^2 + k$, where $(h, k)$ is the vertex of the parabola. Given $g(x) = \frac{1}{3}\left(x + \frac{24}{5}\right)^2 - \frac{5}{24}$, we can see it is already in vertex form with $h = -\frac{24}{5}$ and $k = -\frac{5}{24}$, making the vertex $\left(-\frac{24}{5}, -\frac{5}{24}\right)$.

Find the Vertex Of g(x)=13(x+245)2−524g ( x ) = \frac { 1 } { 3 } \left( x + \frac { 24 } { 5 } \right) ^ { 2 } - \frac { 5 } { 24 }g(x)=31​(x+524​)2−245​

Find the Vertex Of $g ( x ) = \frac { 1 } { 3 } \left( x + \frac { 24 } { 5 } \right) ^ { 2 } - \frac { 5 } { 24 }$