Solve the equation by using the quadratic formula. $$0.01 x ^ { 2 } + 0.1 x + 0.24 = 0$$
A) {-0.06, -0.04}
B) {-6, -4}
C) {0.06i, 0.04i}
D) {4i, 6i}

Question

Quizplus · Accepted Answer

The quadratic formula is used to find the roots of the equation: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$. Here, $a = 0.01$, $b = 0.1$, and $c = 0.24$. Calculating the discriminant $b^2 - 4ac = 0.01 - 0.0096 = 0.0004$, which is positive, so the roots are real. Solving gives roots -6 and -4.

Solve the Equation by Using the Quadratic Formula 0.01x2+0.1x+0.24=00.01 x ^ { 2 } + 0.1 x + 0.24 = 00.01x2+0.1x+0.24=0

Solve the Equation by Using the Quadratic Formula $0.01 x ^ { 2 } + 0.1 x + 0.24 = 0$