Solve for $a . ( a 0 )$
$$a ^ { 2 } + b ^ { 2 } + c ^ { 2 } = d ^ { 2 }$$
A) $a = \pm \sqrt { d ^ { 2 } - b ^ { 2 } - c ^ { 2 } }$
B) $a = \sqrt { d ^ { 2 } - b ^ { 2 } - c ^ { 2 } }$
C) $a = d - b - c$
D) $a = \pm ( d - b - c )$

Question

Solve for $a . ( a > 0 )$
$$a ^ { 2 } + b ^ { 2 } + c ^ { 2 } = d ^ { 2 }$$
A) $a = \pm \sqrt { d ^ { 2 } - b ^ { 2 } - c ^ { 2 } }$
B) $a = \sqrt { d ^ { 2 } - b ^ { 2 } - c ^ { 2 } }$
C) $a = d - b - c$
D) $a = \pm ( d - b - c )$

Quizplus · Accepted Answer

Given $a > 0$, the correct solution is $a = \sqrt { d ^ { 2 } - b ^ { 2 } - c ^ { 2 } }$, as it ensures $a$ is positive.

Solve For a.(a>0)a . ( a > 0 )a.(a>0) a2+b2+c2=d2a ^ { 2 } + b ^ { 2 } + c ^ { 2 } = d ^ { 2 }a2+b2+c2=d2

Solve For $a . ( a > 0 )$ $a ^ { 2 } + b ^ { 2 } + c ^ { 2 } = d ^ { 2 }$