Find the value of k so that the expression is a perfect square trinomial and then factor the trinomial. $$y ^ { 2 } - 8 y + k$$
A) $k = 16 ; ( y - 4 )$
B) $k = 4 ; ( y - 4 ) ^ { 2 }$
C) $k = 4 ; ( y + 4 ) ^ { 2 }$
D) $k = 16 ; ( y - 4 ) ^ { 2 }$

Question

Quizplus · Accepted Answer

For a trinomial $y^2 - 8y + k$ to be a perfect square, $k$ must be $(\frac{-8}{2})^2 = 16$. Factoring gives $(y - 4)^2$.

Find the Value of K So That the Expression Is y2−8y+ky ^ { 2 } - 8 y + ky2−8y+k

Find the Value of K So That the Expression Is $y ^ { 2 } - 8 y + k$