Answer the question.
-Police use a formula s $= S \sqrt { \frac { l } { L } }$, where $S$ is the test-car speed and $L$ is the test-skid length, to find the actual speed $s$ in an accident which left a skid mark of 1 . Find the speed (nearest whole mph) when $S = 63 \mathrm { mph }$, $\mathrm { l } = 150 \mathrm { ft } , \mathrm { L } = 100 \mathrm { ft } .$
A) $52 \mathrm { mph }$
B) $95 \mathrm { mph }$
C) $113 \mathrm { mph }$
D) $77 \mathrm { mph }$

Question

Quizplus · Accepted Answer

Using the formula $s = S \sqrt{\frac{l}{L}}$, substitute $S = 63$, $l = 150$, and $L = 100$: $s = 63 \sqrt{\frac{150}{100}} = 63 \sqrt{1.5} \approx 77$ mph.

Answer the Question =SlL= S \sqrt { \frac { l } { L } }=SLl​​

Answer the Question $= S \sqrt { \frac { l } { L } }$