Determine the nature of the solutions of the equation.
-$$s ^ { 2 } - 6 s - 7 = 0$$
A) Two nonreal
B) Two real
C) One real

Question

Quizplus · Accepted Answer

The discriminant of a quadratic equation $ax^2 + bx + c = 0$ is given by $b^2 - 4ac$. For the given equation, $a = 1$, $b = -6$, and $c = -7$, so the discriminant is $(-6)^2 - 4(1)(-7) = 36 + 28 = 64$. Since the discriminant is positive, the equation has two real solutions.

Determine the Nature of the Solutions of the Equation s2−6s−7=0s ^ { 2 } - 6 s - 7 = 0s2−6s−7=0

Determine the Nature of the Solutions of the Equation $s ^ { 2 } - 6 s - 7 = 0$