Solve. Give exact solutions.
-$$x ^ { 2 } + 12 x + 36 = 17$$
A) 11
B) $\sqrt { 17 } , \sqrt { 17 }$
C) $- 6 + \sqrt { 17 } , - 6 - \sqrt { 17 }$
D) $6 + \sqrt { 17 } , 6 - \sqrt { 17 }$

Question

Quizplus · Accepted Answer

The equation can be rewritten as $x^2 + 12x + 36 - 17 = 0$, simplifying to $x^2 + 12x + 19 = 0$. Using the quadratic formula, $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, with $a = 1$, $b = 12$, and $c = 19$, we find the solutions to be $x = -6 \pm \sqrt{17}$.

Solve Give Exact Solutions x2+12x+36=17x ^ { 2 } + 12 x + 36 = 17x2+12x+36=17

Solve Give Exact Solutions $x ^ { 2 } + 12 x + 36 = 17$