Solve the problem.
-Find the length of a rectangular lot with a perimeter of 122 meters if the length is 5 meters more than the width. (P = 2L + 2W)
A)61 m
B)33 m
C)28 m
D)66 m

Question

Quizplus · Accepted Answer

Let the width be W meters. Then the length is W + 5 meters. The perimeter is given by P = 2L + 2W = 122. Substituting L = W + 5, we get 2(W + 5) + 2W = 122. Simplifying, 2W + 10 + 2W = 122, which gives 4W + 10 = 122. Solving for W, we get 4W = 112, so W = 28. Therefore, the length L = W + 5 = 28 + 5 = 33 meters.

Solve the Problem. -Find the Length of a Rectangular Lot with a Perimeter