Factor.
-$$x ^ { 2 } - 0.9 x + 0.14$$
A) $( x + 0.7 ) ( x - 0.2 )$
B) $( x - 0.7 ) ( x + 0.2 )$
C) $( x - 0.7 ) ( x - 0.2 )$
D) $( x - 0.45 ) ^ { 2 }$

Name: Factor. -\[x ^ { 2 } - 0.9 x + 0.14\] A) $( x + 0.7 ) ( x - 0.2 )$ B) $( x - 0.7 ) ( x + 0.2 )$ C) $( x - 0.7 ) ( x - 0.2 )$ D) $( x - 0.45 ) ^ { 2 }$
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Question

Quizplus · Accepted Answer

The correct factorization of $x^2 - 0.9x + 0.14$ is $(x - 0.7)(x - 0.2)$, as multiplying these two factors gives the original quadratic equation.

Factor - x2−0.9x+0.14x ^ { 2 } - 0.9 x + 0.14x2−0.9x+0.14

Factor
- $x ^ { 2 } - 0.9 x + 0.14$