Find an equation of variation in which the following are true.
-$x$ varies inversely as $y ^ { 2 }$, and $x = 10$ when $y = 16$.
A) $x = \frac { 1 } { - 6 y ^ { 2 } }$
B) $x = 2560 y ^ { 2 }$
C) $x = \frac { 1 } { 2560 y ^ { 2 } }$
D) $x = \frac { 2560 } { y ^ { 2 } }$

Question

Quizplus · Accepted Answer

Inverse variation is given by $x = \frac{k}{y^2}$, where $k$ is the constant of variation. To find $k$, use $x = 10$ when $y = 16$: $10 = \frac{k}{16^2}$, so $k = 10 \times 16^2 = 2560$. Thus, the equation is $x = \frac{2560}{y^2}$.

Find an Equation of Variation in Which the Following Are xxx

Find an Equation of Variation in Which the Following Are $x$