Subtract. Simplify, if possible.
-$\frac { 3 } { 14 x } - \frac { 9 } { 10 x ^ { 2 } }$
A) $\frac { 18 } { 70 x ^ { 2 } }$
B) $\frac { 3 ( 5 x - 21 ) } { 70 x ^ { 2 } }$
C) $- \frac { 6 } { 140 x ^ { 2 } }$
D) $\frac { - 6 } { 14 x + 10 x ^ { 2 } }$

Question

Quizplus · Accepted Answer

To subtract the fractions, first find a common denominator, which is $70x^2$ (the least common multiple of $14x$ and $10x^2$). Convert each fraction to have this common denominator, then subtract: $\frac{3}{14x} = \frac{3 \cdot 5x}{14x \cdot 5x} = \frac{15x}{70x^2}$ and $\frac{9}{10x^2} = \frac{9 \cdot 7}{10x^2 \cdot 7} = \frac{63}{70x^2}$. Subtracting gives $\frac{15x - 63}{70x^2} = \frac{3(5x - 21)}{70x^2}$.

Subtract Simplify, If Possible 314x−910x2\frac { 3 } { 14 x } - \frac { 9 } { 10 x ^ { 2 } }14x3​−10x29​

Subtract Simplify, If Possible $\frac { 3 } { 14 x } - \frac { 9 } { 10 x ^ { 2 } }$