Solve.
-John and Tony start from GraysLake at the same time and head for a town 10 miles away. John walks twice as fast as Tony and arrives 3 hours before Tony. Find how fast each walks.
A) Tony's speed $= 3 \mathrm {~m} / \mathrm { h }$ and John's $= 6 \mathrm {~m} / \mathrm { h }$.
B) Tony's speed $= \frac { 5 } { 3 } \mathrm {~m} / \mathrm { h }$ and John's $= \frac { 10 } { 3 } \mathrm {~m} / \mathrm { h }$.
C) Tony's speed $= \frac { 3 } { 5 } \mathrm {~m} / \mathrm { h }$ and John's $= \frac { 6 } { 5 } \mathrm {~m} / \mathrm { h }$.
D) Cannot be determined with information given

Question

Quizplus · Accepted Answer

Let Tony's speed be $ x $ miles per hour. Then John's speed is $ 2x $ miles per hour. The time taken by Tony is $ \frac{10}{x} $ hours and by John is $ \frac{10}{2x} = \frac{5}{x} $ hours. Since John arrives 3 hours before Tony, we have $ \frac{10}{x} - \frac{5}{x} = 3 $. Solving this gives $ x = \frac{5}{3} $ miles per hour for Tony and $ 2x = \frac{10}{3} $ miles per hour for John.

Solve -John and Tony Start from GraysLake at the Same =3 m/h= 3 \mathrm {~m} / \mathrm { h }=3 m/h

Solve
-John and Tony Start from GraysLake at the Same $= 3 \mathrm {~m} / \mathrm { h }$