Solve the problem.
-How many liters of a 10% alcohol solution must be mixed with 90 liters of a 70% solution to get a 60% solution?
A)108 L
B)1.8 L
C)18 L
D)10.8 L

Name: Solve the problem. -How many liters of a 10% alcohol solution must be mixed with 90 liters of a 70% solution to get a 60% solution? A)108 L B)1.8 L C)18 L D)10.8 L
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Question

Quizplus · Accepted Answer

To find the amount of 10% solution needed, set up the equation: 0.10x + 0.70(90) = 0.60(x + 90). Solving for x gives x = 18 liters.

Solve the Problem. -How Many Liters of a 10% Alcohol Solution Must Be