Solve.
-The temperature at 5:00 was $- 6 ^ { \circ } \mathrm { C }$. Four hours later, it was $- 10 ^ { \circ } \mathrm { C }$. What was the change in temperature?
A) $16 ^ { \circ } \mathrm { C }$
B) $- 16 ^ { \circ } \mathrm { C }$
C) $- 4 ^ { \circ } \mathrm { C }$
D) $4 ^ { \circ } \mathrm { C }$

Question

Quizplus · Accepted Answer

The change in temperature is found by subtracting the initial temperature from the final temperature: $-10 ^ { \circ } \mathrm { C } - (-6 ^ { \circ } \mathrm { C }) = -4 ^ { \circ } \mathrm { C }$.

Solve -The Temperature at 5:00 Was −6∘C- 6 ^ { \circ } \mathrm { C }−6∘C

Solve
-The Temperature at 5:00 Was $- 6 ^ { \circ } \mathrm { C }$