Solve.
-$x - 8 \sqrt { x } + 12 = 0$
A) 36,4
B) $- \sqrt { 6 } , \sqrt { 6 } , - \sqrt { 2 } , \sqrt { 2 }$
C) 6,2
D) $- 6,6 , - 2,2$

Question

Quizplus · Accepted Answer

This equation can be solved by recognizing it as a quadratic equation in disguise. Let $y = \sqrt{x}$, then the equation becomes $y^2 - 8y + 12 = 0$. Factoring this gives $(y-6)(y-2) = 0$, so $y = 6$ or $y = 2$. Substituting back for $x$, we get $x = 36$ or $x = 4$.

Solve - x−8x+12=0x - 8 \sqrt { x } + 12 = 0x−8x​+12=0

Solve
- $x - 8 \sqrt { x } + 12 = 0$