Solve.
-$x ^ { 3 } + x - 8 x ^ { 2 } - 8 = 0$
A) $8 , - \mathrm { i } , \mathrm { i }$
B) $- 8 , - \mathrm { i } , \mathrm { i }$
C) $- 1,1 , - 8 i , 8 i$
D) $- 1,1 , - 8,8$

Question

Quizplus · Accepted Answer

The given equation can be rewritten as $x^3 - 8x^2 + x - 8 = 0$, which can be factored into $(x-8)(x^2+1) = 0$. Solving for $x$ gives the roots $x = 8$, $x = i$, and $x = -i$.

Solve - x3+x−8x2−8=0x ^ { 3 } + x - 8 x ^ { 2 } - 8 = 0x3+x−8x2−8=0

Solve
- $x ^ { 3 } + x - 8 x ^ { 2 } - 8 = 0$