Solve.
-A rectangular sign must have an area of 23 square yards. Its length must be 2 yards more than its width. Find the dimensions of the sign.
A) $( 1 + 2 \sqrt { 6 } )$ yd by $( - 1 + 2 \sqrt { 6 } ) y d$
B) $( 1 - 2 \sqrt { 6 } )$ yd by $( - 1 - 2 \sqrt { 6 } ) y d$
C) $( 1 - 2 \sqrt { 6 } ) \mathrm { yd }$ by $( 1 + 2 \sqrt { 6 } ) \mathrm { yd }$
D) $( 1 + 2 \sqrt { 6 } )$ yd by $( 3 + 2 \sqrt { 6 } ) y d$

Question

Quizplus · Accepted Answer

The equation for the area of the rectangle is $w(w + 2) = 23$, where $w$ is the width and $w + 2$ is the length. Solving this quadratic equation gives the dimensions as $( 1 + 2 \sqrt { 6 } )$ yd by $( - 1 + 2 \sqrt { 6 } ) yd$.

Solve -A Rectangular Sign Must Have an Area of 23 (1+26)( 1 + 2 \sqrt { 6 } )(1+26​)

Solve
-A Rectangular Sign Must Have an Area of 23 $( 1 + 2 \sqrt { 6 } )$