Solve for x.
-$\log _ { 5 } \frac { 1 } { 25 } = x$
A) $\frac { 1 } { 125 }$
B) 2
C) $- 2$
D) $\frac { 1 } { 5 }$

Name: Solve for x. -$\log _ { 5 } \frac { 1 } { 25 } = x$ A) $\frac { 1 } { 125 }$ B) 2 C) $- 2$ D) $\frac { 1 } { 5 }$
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Question

Quizplus · Accepted Answer

The equation $\log_5 \frac{1}{25} = x$ can be rewritten using the property of logarithms that $\log_b a^n = n \log_b a$. Since $25 = 5^2$, and we're taking the log base 5 of 1/25, it's equivalent to $\log_5 5^{-2}$, which simplifies to $-2$. Therefore, $x = -2$.

Solve for X log⁡5125=x\log _ { 5 } \frac { 1 } { 25 } = xlog5​251​=x

Solve for X $\log _ { 5 } \frac { 1 } { 25 } = x$