Solve.
-Four bacteria are placed in a petri dish. The population will triple every day. The formula for the number of bacteria in the dish on day $t$ is $N ( t ) = 4 ( 3 ) ^ { t }$, where $t$ is the number of days after the four bacteria are placed in the dish. How many bacteria are in the dish seven days after the four bacteria are placed in the dish?
A) 1372 bacteria
B) 8748 bacteria
C) 14 bacteria
D) 84 bacteria

Question

Quizplus · Accepted Answer

The formula $N(t) = 4(3)^t$ is used to calculate the number of bacteria. For $t = 7$, $N(7) = 4(3)^7 = 4 \times 2187 = 8748$ bacteria.

Solve -Four Bacteria Are Placed in a Petri Dish ttt Is N(t)=4(3)tN ( t ) = 4 ( 3 ) ^ { t }N(t)=4(3)t

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-Four Bacteria Are Placed in a Petri Dish $t$ Is $N ( t ) = 4 ( 3 ) ^ { t }$