Solve.
-A rectangular holding pen for sheep is to be designed so that its perimeter is 22 meters and its area is 24 square meters. Find the dimensions of the holding pen.
A) $3 \mathrm {~m}$ by $8 \mathrm {~m}$
B) $4 \mathrm {~m}$ by $7 \mathrm {~m}$
C) $2 \mathrm {~m}$ by $9 \mathrm {~m}$
D) $2 \mathrm {~m}$ by $7 \mathrm {~m}$

Question

Solve.
-A rectangular holding pen for sheep is to be designed so that its perimeter is 22 meters and its area is 24 square meters. Find the dimensions of the holding pen. 
A) $3 \mathrm {~m}$ by $8 \mathrm {~m}$
B) $4 \mathrm {~m}$ by $7 \mathrm {~m}$
C) $2 \mathrm {~m}$ by $9 \mathrm {~m}$
D) $2 \mathrm {~m}$ by $7 \mathrm {~m}$

Quizplus · Accepted Answer

The dimensions that satisfy both the perimeter and area conditions are $3 \mathrm {~m}$ by $8 \mathrm {~m}$. The perimeter of a rectangle is given by $2l + 2w = 22$ and the area by $lw = 24$. Solving these equations simultaneously, we find that $l = 3$ and $w = 8$ meet both conditions.

Solve -A Rectangular Holding Pen for Sheep Is to Be 3 m3 \mathrm {~m}3 m

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-A Rectangular Holding Pen for Sheep Is to Be $3 \mathrm {~m}$