Solve the problem.
-Find the sum of the first ten negative integers.
A) $- 45$
B) $- 55$
C) $- 56$
D) $- 66$

Question

Quizplus · Accepted Answer

The first ten negative integers are -1, -2, -3, ..., -10. The sum of an arithmetic series is given by $S = \frac{n}{2}(a_1 + a_n)$, where $n$ is the number of terms, $a_1$ is the first term, and $a_n$ is the last term. Here, $n = 10$, $a_1 = -1$, and $a_n = -10$, so $S = \frac{10}{2}(-1 - 10) = 5 \times -11 = -55$.

Solve the Problem −45- 45−45 B) −55- 55−55 C) −56- 56−56 D) −66- 66−66

Solve the Problem $- 45$ B) $- 55$ C) $- 56$ D) $- 66$