Given are the first three terms of a sequence that is geometric. Find a1 and r.
-$\frac { 3 } { 1 } , \frac { 3 } { 4 } , \frac { 3 } { 16 }$
A) $a _ { 1 } = \frac { 3 } { 1 } ; r = \frac { 1 } { 10 }$
B) $\mathrm { a } _ { 1 } = \frac { 3 } { 1 } ; \mathrm { r } = \frac { 1 } { 4 }$
C) $a _ { 1 } = \frac { 3 } { 1 } ; r = 4$
D) $\mathrm { a } _ { 1 } = \frac { 3 } { 1 } ; \mathrm { r } = 10$

Question

Quizplus · Accepted Answer

The first term $a_1$ is $\frac{3}{1}$, and the common ratio $r$ can be found by dividing the second term by the first term, or the third term by the second term, which gives $\frac{1}{4}$.

Given Are the First Three Terms of a Sequence That 31,34,316\frac { 3 } { 1 } , \frac { 3 } { 4 } , \frac { 3 } { 16 }13​,43​,163​

Given Are the First Three Terms of a Sequence That $\frac { 3 } { 1 } , \frac { 3 } { 4 } , \frac { 3 } { 16 }$