Solve the problem.
-Sue took her collection of nickels and dimes to deposit in the bank. She has five fewer nickels than dimes. Her total deposit was $45.35. How many dimes did she deposit?
A) 299 dimes
B) 309 dimes
C) 304 dimes
D) 603 dimes

Question

Quizplus · Accepted Answer

Let the number of dimes be $d$ and the number of nickels be $n$. The problem states that Sue has five fewer nickels than dimes, so $n = d - 5$. The total value of the coins is $45.35, or 4535 cents. Since dimes are worth 10 cents and nickels are worth 5 cents, the total value can be represented as $10d + 5n = 4535$. Substituting $n = d - 5$ into the equation gives $10d + 5(d - 5) = 4535$, which simplifies to $15d - 25 = 4535$. Solving for $d$ gives $d = 304$, so Sue deposited 304 dimes.

Solve the Problem. -Sue Took Her Collection of Nickels and Dimes to Deposit