Solve.
-The length of a rectangular room is 3 feet longer than twice the width. If the room's perimeter is 126 feet, what are the room's dimensions?
A) Width = 40 ft; length = 86 ft
B) Width = 30 ft; length = 33 ft
C) Width = 25 ft; length = 53 ft
D) Width = 20 ft; length = 43 ft

Question

Quizplus · Accepted Answer

The perimeter of a rectangle is given by the formula $P = 2l + 2w$, where $l$ is the length and $w$ is the width. Given that the length ($l$) is 3 feet longer than twice the width ($w$), we can express the length as $l = 2w + 3$. Substituting this into the perimeter formula with $P = 126$ feet gives $126 = 2(2w + 3) + 2w$. Solving this equation for $w$ gives $w = 20$ feet. Substituting $w = 20$ feet back into the expression for the length gives $l = 2(20) + 3 = 43$ feet. Therefore, the dimensions are width = 20 ft and length = 43 ft.

Solve. -The Length of a Rectangular Room Is 3 Feet Longer