Solve. Assume the exercise describes a linear relationship.
-A vendor has learned that, by pricing pretzels at $\$ 1.75$, sales will reach 83 pretzels per day. Raising the price to $\$ 2.25$ will cause the sales to fall to 59 pretzels per day. Let y be the number of pretzels the vendor sells at $x$ dollars each. Write a linear equation that models the number of pretzels sold per day when the price is $x$ dollars each.
A) $y = - 48 x + 167$
B) $y = - \frac { 1 } { 48 } x + \frac { 15929 } { 192 }$
C) $y = - 48 x - 167$
D) $y = 48 x - 1$

Question

Quizplus · Accepted Answer

The linear equation can be found using the two given points: (1.75, 83) and (2.25, 59). The slope (m) is $\frac{59 - 83}{2.25 - 1.75} = \frac{-24}{0.5} = -48$. Using the point-slope form with one of the points, for example, (1.75, 83), we get $y - 83 = -48(x - 1.75)$. Simplifying, $y = -48x + 48 \times 1.75 + 83 = -48x + 167$.

Solve Assume the Exercise Describes a Linear Relationship $1.75\$ 1.75$1.75 , Sales Will Reach 83 Pretzels Per Day

Solve Assume the Exercise Describes a Linear Relationship $\$ 1.75$ , Sales Will Reach 83 Pretzels Per Day