Solve Assume the Exercise Describes a Linear Relationship $\$ 3441$ In 2007 by 2011 It Has Grown To Relationship

Solve. Assume the exercise describes a linear relationship.
-An investment is worth $\$ 3441$ in 2007. By 2011 it has grown to $\$ 5181$ . Let $y$ be the value of the investment in the year $\mathrm { x }$ , where $\mathrm { x } = 0$ represents 2007. Write a linear equation that models the value of the investment in the year $\mathrm { x }$ .

A) $y = - 435 x + 6921$
B) $y = \frac { 1 } { 435 } x + 3441$
C) $y = - 435 x + 3441$
D) $y = 435 x + 3441$