Solve.
-Jamil always throws loose change into a pencil holder on his desk and takes it out every two weeks. This time it is all nickels and dimes. There are 7 times as many dimes as nickels, and the value of the dimes is $\$ 7.80$ more than the value of the nickels. How many nickels and dimes does Jamil have?
A) 12 nickels and 84 dimes
B) 84 nickels and 12 dimes
C) 11 nickels and 77 dimes
D) 13 nickels and 91 dimes

Question

Quizplus · Accepted Answer

Let the number of nickels be $n$ and the number of dimes be $d$. Given that $d = 7n$ and the value difference is $7.80$, we can set up the equations: $0.10d - 0.05n = 7.80$ and $d = 7n$. Solving these equations gives us $n = 12$ and $d = 84$, which corresponds to choice A.

Solve -Jamil Always Throws Loose Change into a Pencil Holder $7.80\$ 7.80$7.80

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-Jamil Always Throws Loose Change into a Pencil Holder $\$ 7.80$