Solve.
-One number is 6 less than a second number. Twice the second number is 40 more than 4 times the first. Find the two numbers.
A) -13 and -7
B) 8 and 14
C) -14 and -8
D) -15 and -9

Question

Quizplus · Accepted Answer

Let the first number be $x$ and the second number be $y$. The given information translates to two equations: $x = y - 6$ and $2y = 4x + 40$. Substituting the first equation into the second gives $2y = 4(y - 6) + 40$, which simplifies to $2y = 4y - 24 + 40$, leading to $2y = 4y + 16$. Solving for $y$ gives $y = -8$, and substituting back gives $x = -14$.

Solve. -One Number Is 6 Less Than a Second Number. Twice